2(v-3)-4=-6(-3v+1)-6v

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Solution for 2(v-3)-4=-6(-3v+1)-6v equation: 



2(v-3)-4=-6(-3v+1)-6v

We move all terms to the left:

2(v-3)-4-(-6(-3v+1)-6v)=0

We multiply parentheses

2v-(-6(-3v+1)-6v)-6-4=0



We calculate terms in parentheses: -(-6(-3v+1)-6v), so:

-6(-3v+1)-6v

We add all the numbers together, and all the variables

-6v-6(-3v+1)

We multiply parentheses

-6v+18v-6

We add all the numbers together, and all the variables

12v-6

Back to the equation:

-(12v-6)



We add all the numbers together, and all the variables

2v-(12v-6)-10=0

We get rid of parentheses

2v-12v+6-10=0

We add all the numbers together, and all the variables

-10v-4=0

We move all terms containing v to the left, all other terms to the right

-10v=4

v=4/-10

v=-2/5

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