2(v-3)=5v+4-3(-3v-2)

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Solution for 2(v-3)=5v+4-3(-3v-2) equation: 



2(v-3)=5v+4-3(-3v-2)

We move all terms to the left:

2(v-3)-(5v+4-3(-3v-2))=0

We multiply parentheses

2v-(5v+4-3(-3v-2))-6=0



We calculate terms in parentheses: -(5v+4-3(-3v-2)), so:

5v+4-3(-3v-2)

determiningTheFunctionDomain
5v-3(-3v-2)+4

We multiply parentheses

5v+9v+6+4

We add all the numbers together, and all the variables

14v+10

Back to the equation:

-(14v+10)



We get rid of parentheses

2v-14v-10-6=0

We add all the numbers together, and all the variables

-12v-16=0

We move all terms containing v to the left, all other terms to the right

-12v=16

v=16/-12

v=-1+1/3

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