2(v-4)-3=-3(-6v+5)-6v

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Solution for 2(v-4)-3=-3(-6v+5)-6v equation: 



2(v-4)-3=-3(-6v+5)-6v

We move all terms to the left:

2(v-4)-3-(-3(-6v+5)-6v)=0

We multiply parentheses

2v-(-3(-6v+5)-6v)-8-3=0



We calculate terms in parentheses: -(-3(-6v+5)-6v), so:

-3(-6v+5)-6v

We add all the numbers together, and all the variables

-6v-3(-6v+5)

We multiply parentheses

-6v+18v-15

We add all the numbers together, and all the variables

12v-15

Back to the equation:

-(12v-15)



We add all the numbers together, and all the variables

2v-(12v-15)-11=0

We get rid of parentheses

2v-12v+15-11=0

We add all the numbers together, and all the variables

-10v+4=0

We move all terms containing v to the left, all other terms to the right

-10v=-4

v=-4/-10

v=2/5

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