2(v-4)-4=-2(-8v+3)-2v

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Solution for 2(v-4)-4=-2(-8v+3)-2v equation: 



2(v-4)-4=-2(-8v+3)-2v

We move all terms to the left:

2(v-4)-4-(-2(-8v+3)-2v)=0

We multiply parentheses

2v-(-2(-8v+3)-2v)-8-4=0



We calculate terms in parentheses: -(-2(-8v+3)-2v), so:

-2(-8v+3)-2v

We add all the numbers together, and all the variables

-2v-2(-8v+3)

We multiply parentheses

-2v+16v-6

We add all the numbers together, and all the variables

14v-6

Back to the equation:

-(14v-6)



We add all the numbers together, and all the variables

2v-(14v-6)-12=0

We get rid of parentheses

2v-14v+6-12=0

We add all the numbers together, and all the variables

-12v-6=0

We move all terms containing v to the left, all other terms to the right

-12v=6

v=6/-12

v=-1/2

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