2(v-4)-4=-3(-7v+2)-4v

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Solution for 2(v-4)-4=-3(-7v+2)-4v equation: 



2(v-4)-4=-3(-7v+2)-4v

We move all terms to the left:

2(v-4)-4-(-3(-7v+2)-4v)=0

We multiply parentheses

2v-(-3(-7v+2)-4v)-8-4=0



We calculate terms in parentheses: -(-3(-7v+2)-4v), so:

-3(-7v+2)-4v

We add all the numbers together, and all the variables

-4v-3(-7v+2)

We multiply parentheses

-4v+21v-6

We add all the numbers together, and all the variables

17v-6

Back to the equation:

-(17v-6)



We add all the numbers together, and all the variables

2v-(17v-6)-12=0

We get rid of parentheses

2v-17v+6-12=0

We add all the numbers together, and all the variables

-15v-6=0

We move all terms containing v to the left, all other terms to the right

-15v=6

v=6/-15

v=-2/5

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