2(v-4)=2(v-8)+8

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Solution for 2(v-4)=2(v-8)+8 equation: 



2(v-4)=2(v-8)+8

We move all terms to the left:

2(v-4)-(2(v-8)+8)=0

We multiply parentheses

2v-(2(v-8)+8)-8=0



We calculate terms in parentheses: -(2(v-8)+8), so:

2(v-8)+8

We multiply parentheses

2v-16+8

We add all the numbers together, and all the variables

2v-8

Back to the equation:

-(2v-8)



We get rid of parentheses

2v-2v+8-8=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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