2(v-4)=4v-22

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Solution for 2(v-4)=4v-22 equation: 



2(v-4)=4v-22

We move all terms to the left:

2(v-4)-(4v-22)=0

We multiply parentheses

2v-(4v-22)-8=0

We get rid of parentheses

2v-4v+22-8=0

We add all the numbers together, and all the variables

-2v+14=0

We move all terms containing v to the left, all other terms to the right

-2v=-14

v=-14/-2

v=+7

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