2(v-5)-4=-6(-3v+5)-4v

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Solution for 2(v-5)-4=-6(-3v+5)-4v equation: 



2(v-5)-4=-6(-3v+5)-4v

We move all terms to the left:

2(v-5)-4-(-6(-3v+5)-4v)=0

We multiply parentheses

2v-(-6(-3v+5)-4v)-10-4=0



We calculate terms in parentheses: -(-6(-3v+5)-4v), so:

-6(-3v+5)-4v

We add all the numbers together, and all the variables

-4v-6(-3v+5)

We multiply parentheses

-4v+18v-30

We add all the numbers together, and all the variables

14v-30

Back to the equation:

-(14v-30)



We add all the numbers together, and all the variables

2v-(14v-30)-14=0

We get rid of parentheses

2v-14v+30-14=0

We add all the numbers together, and all the variables

-12v+16=0

We move all terms containing v to the left, all other terms to the right

-12v=-16

v=-16/-12

v=1+1/3

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