2(v-5)-5=-4(-5v+3)-3v

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Solution for 2(v-5)-5=-4(-5v+3)-3v equation: 



2(v-5)-5=-4(-5v+3)-3v

We move all terms to the left:

2(v-5)-5-(-4(-5v+3)-3v)=0

We multiply parentheses

2v-(-4(-5v+3)-3v)-10-5=0



We calculate terms in parentheses: -(-4(-5v+3)-3v), so:

-4(-5v+3)-3v

We add all the numbers together, and all the variables

-3v-4(-5v+3)

We multiply parentheses

-3v+20v-12

We add all the numbers together, and all the variables

17v-12

Back to the equation:

-(17v-12)



We add all the numbers together, and all the variables

2v-(17v-12)-15=0

We get rid of parentheses

2v-17v+12-15=0

We add all the numbers together, and all the variables

-15v-3=0

We move all terms containing v to the left, all other terms to the right

-15v=3

v=3/-15

v=-1/5

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