2(v-5)-6=-3(-6v+2)-v

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Solution for 2(v-5)-6=-3(-6v+2)-v equation: 



2(v-5)-6=-3(-6v+2)-v

We move all terms to the left:

2(v-5)-6-(-3(-6v+2)-v)=0

We multiply parentheses

2v-(-3(-6v+2)-v)-10-6=0



We calculate terms in parentheses: -(-3(-6v+2)-v), so:

-3(-6v+2)-v

We add all the numbers together, and all the variables

-1v-3(-6v+2)

We multiply parentheses

-1v+18v-6

We add all the numbers together, and all the variables

17v-6

Back to the equation:

-(17v-6)



We add all the numbers together, and all the variables

2v-(17v-6)-16=0

We get rid of parentheses

2v-17v+6-16=0

We add all the numbers together, and all the variables

-15v-10=0

We move all terms containing v to the left, all other terms to the right

-15v=10

v=10/-15

v=-2/3

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