2(v-5)-6=-6(-3v+2)-6v

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Solution for 2(v-5)-6=-6(-3v+2)-6v equation:



2(v-5)-6=-6(-3v+2)-6v
We move all terms to the left:
2(v-5)-6-(-6(-3v+2)-6v)=0
We multiply parentheses
2v-(-6(-3v+2)-6v)-10-6=0
We calculate terms in parentheses: -(-6(-3v+2)-6v), so:
-6(-3v+2)-6v
We add all the numbers together, and all the variables
-6v-6(-3v+2)
We multiply parentheses
-6v+18v-12
We add all the numbers together, and all the variables
12v-12
Back to the equation:
-(12v-12)
We add all the numbers together, and all the variables
2v-(12v-12)-16=0
We get rid of parentheses
2v-12v+12-16=0
We add all the numbers together, and all the variables
-10v-4=0
We move all terms containing v to the left, all other terms to the right
-10v=4
v=4/-10
v=-2/5

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