2(v-6)-4=-3(-3v+2)-v

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Solution for 2(v-6)-4=-3(-3v+2)-v equation: 



2(v-6)-4=-3(-3v+2)-v

We move all terms to the left:

2(v-6)-4-(-3(-3v+2)-v)=0

We multiply parentheses

2v-(-3(-3v+2)-v)-12-4=0



We calculate terms in parentheses: -(-3(-3v+2)-v), so:

-3(-3v+2)-v

We add all the numbers together, and all the variables

-1v-3(-3v+2)

We multiply parentheses

-1v+9v-6

We add all the numbers together, and all the variables

8v-6

Back to the equation:

-(8v-6)



We add all the numbers together, and all the variables

2v-(8v-6)-16=0

We get rid of parentheses

2v-8v+6-16=0

We add all the numbers together, and all the variables

-6v-10=0

We move all terms containing v to the left, all other terms to the right

-6v=10

v=10/-6

v=-1+2/3

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