2(v-6)-4=-7(-3v+4)-v

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Solution for 2(v-6)-4=-7(-3v+4)-v equation: 



2(v-6)-4=-7(-3v+4)-v

We move all terms to the left:

2(v-6)-4-(-7(-3v+4)-v)=0

We multiply parentheses

2v-(-7(-3v+4)-v)-12-4=0



We calculate terms in parentheses: -(-7(-3v+4)-v), so:

-7(-3v+4)-v

We add all the numbers together, and all the variables

-1v-7(-3v+4)

We multiply parentheses

-1v+21v-28

We add all the numbers together, and all the variables

20v-28

Back to the equation:

-(20v-28)



We add all the numbers together, and all the variables

2v-(20v-28)-16=0

We get rid of parentheses

2v-20v+28-16=0

We add all the numbers together, and all the variables

-18v+12=0

We move all terms containing v to the left, all other terms to the right

-18v=-12

v=-12/-18

v=2/3

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