2(v-6)-6=-3(-4v+1)-4v

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Solution for 2(v-6)-6=-3(-4v+1)-4v equation: 



2(v-6)-6=-3(-4v+1)-4v

We move all terms to the left:

2(v-6)-6-(-3(-4v+1)-4v)=0

We multiply parentheses

2v-(-3(-4v+1)-4v)-12-6=0



We calculate terms in parentheses: -(-3(-4v+1)-4v), so:

-3(-4v+1)-4v

We add all the numbers together, and all the variables

-4v-3(-4v+1)

We multiply parentheses

-4v+12v-3

We add all the numbers together, and all the variables

8v-3

Back to the equation:

-(8v-3)



We add all the numbers together, and all the variables

2v-(8v-3)-18=0

We get rid of parentheses

2v-8v+3-18=0

We add all the numbers together, and all the variables

-6v-15=0

We move all terms containing v to the left, all other terms to the right

-6v=15

v=15/-6

v=-2+1/2

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