2(v-7)-6=-3(-3v+2)-3v

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Solution for 2(v-7)-6=-3(-3v+2)-3v equation: 



2(v-7)-6=-3(-3v+2)-3v

We move all terms to the left:

2(v-7)-6-(-3(-3v+2)-3v)=0

We multiply parentheses

2v-(-3(-3v+2)-3v)-14-6=0



We calculate terms in parentheses: -(-3(-3v+2)-3v), so:

-3(-3v+2)-3v

We add all the numbers together, and all the variables

-3v-3(-3v+2)

We multiply parentheses

-3v+9v-6

We add all the numbers together, and all the variables

6v-6

Back to the equation:

-(6v-6)



We add all the numbers together, and all the variables

2v-(6v-6)-20=0

We get rid of parentheses

2v-6v+6-20=0

We add all the numbers together, and all the variables

-4v-14=0

We move all terms containing v to the left, all other terms to the right

-4v=14

v=14/-4

v=-3+1/2

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