2(v-8)-4=-6(-4v+2)-6v

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Solution for 2(v-8)-4=-6(-4v+2)-6v equation: 



2(v-8)-4=-6(-4v+2)-6v

We move all terms to the left:

2(v-8)-4-(-6(-4v+2)-6v)=0

We multiply parentheses

2v-(-6(-4v+2)-6v)-16-4=0



We calculate terms in parentheses: -(-6(-4v+2)-6v), so:

-6(-4v+2)-6v

We add all the numbers together, and all the variables

-6v-6(-4v+2)

We multiply parentheses

-6v+24v-12

We add all the numbers together, and all the variables

18v-12

Back to the equation:

-(18v-12)



We add all the numbers together, and all the variables

2v-(18v-12)-20=0

We get rid of parentheses

2v-18v+12-20=0

We add all the numbers together, and all the variables

-16v-8=0

We move all terms containing v to the left, all other terms to the right

-16v=8

v=8/-16

v=-1/2

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