2(v-8)-6=-4(-5v+3)-6v

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Solution for 2(v-8)-6=-4(-5v+3)-6v equation: 



2(v-8)-6=-4(-5v+3)-6v

We move all terms to the left:

2(v-8)-6-(-4(-5v+3)-6v)=0

We multiply parentheses

2v-(-4(-5v+3)-6v)-16-6=0



We calculate terms in parentheses: -(-4(-5v+3)-6v), so:

-4(-5v+3)-6v

We add all the numbers together, and all the variables

-6v-4(-5v+3)

We multiply parentheses

-6v+20v-12

We add all the numbers together, and all the variables

14v-12

Back to the equation:

-(14v-12)



We add all the numbers together, and all the variables

2v-(14v-12)-22=0

We get rid of parentheses

2v-14v+12-22=0

We add all the numbers together, and all the variables

-12v-10=0

We move all terms containing v to the left, all other terms to the right

-12v=10

v=10/-12

v=-5/6

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