2(v-9)=7v+32

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Solution for 2(v-9)=7v+32 equation: 



2(v-9)=7v+32

We move all terms to the left:

2(v-9)-(7v+32)=0

We multiply parentheses

2v-(7v+32)-18=0

We get rid of parentheses

2v-7v-32-18=0

We add all the numbers together, and all the variables

-5v-50=0

We move all terms containing v to the left, all other terms to the right

-5v=50

v=50/-5

v=-10

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