2(w+1)+5w=3(w+1)-2

Solution for 2(w+1)+5w=3(w+1)-2 equation:

2(w+1)+5w=3(w+1)-2

We move all terms to the left:

2(w+1)+5w-(3(w+1)-2)=0

We add all the numbers together, and all the variables

5w+2(w+1)-(3(w+1)-2)=0

We multiply parentheses

5w+2w-(3(w+1)-2)+2=0


We calculate terms in parentheses: -(3(w+1)-2), so:

3(w+1)-2

We multiply parentheses

3w+3-2

We add all the numbers together, and all the variables

3w+1

Back to the equation:

-(3w+1)


We add all the numbers together, and all the variables

7w-(3w+1)+2=0

We get rid of parentheses

7w-3w-1+2=0

We add all the numbers together, and all the variables

4w+1=0

We move all terms containing w to the left, all other terms to the right

4w=-1

w=-1/4

w=-1/4