2(w+1)+7=3(w-2)

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Solution for 2(w+1)+7=3(w-2) equation: 



2(w+1)+7=3(w-2)

We move all terms to the left:

2(w+1)+7-(3(w-2))=0

We multiply parentheses

2w-(3(w-2))+2+7=0



We calculate terms in parentheses: -(3(w-2)), so:

3(w-2)

We multiply parentheses

3w-6

Back to the equation:

-(3w-6)



We add all the numbers together, and all the variables

2w-(3w-6)+9=0

We get rid of parentheses

2w-3w+6+9=0

We add all the numbers together, and all the variables

-1w+15=0

We move all terms containing w to the left, all other terms to the right

-w=-15

w=-15/-1

w=+15

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