2(w+1)=-4(4w-5)+3w

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Solution for 2(w+1)=-4(4w-5)+3w equation: 



2(w+1)=-4(4w-5)+3w

We move all terms to the left:

2(w+1)-(-4(4w-5)+3w)=0

We multiply parentheses

2w-(-4(4w-5)+3w)+2=0



We calculate terms in parentheses: -(-4(4w-5)+3w), so:

-4(4w-5)+3w

We add all the numbers together, and all the variables

3w-4(4w-5)

We multiply parentheses

3w-16w+20

We add all the numbers together, and all the variables

-13w+20

Back to the equation:

-(-13w+20)



We get rid of parentheses

2w+13w-20+2=0

We add all the numbers together, and all the variables

15w-18=0

We move all terms containing w to the left, all other terms to the right

15w=18

w=18/15

w=1+1/5

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