2(w+18)2w=244

Solution for 2(w+18)2w=244 equation:

2(w+18)2w=244

We move all terms to the left:

2(w+18)2w-(244)=0

We multiply parentheses

4w^2+72w-244=0

a = 4; b = 72; c = -244;
Δ = b2-4ac
Δ = 722-4·4·(-244)
Δ = 9088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9088}=\sqrt{64*142}=\sqrt{64}*\sqrt{142}=8\sqrt{142}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-8\sqrt{142}}{2*4}=\frac{-72-8\sqrt{142}}{8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+8\sqrt{142}}{2*4}=\frac{-72+8\sqrt{142}}{8}
$