2(w+2)+w=3(w-1)+6

Solution for 2(w+2)+w=3(w-1)+6 equation:

Simplifying
2(w + 2) + w = 3(w + -1) + 6

Reorder the terms:
2(2 + w) + w = 3(w + -1) + 6
(2 * 2 + w * 2) + w = 3(w + -1) + 6
(4 + 2w) + w = 3(w + -1) + 6

Combine like terms: 2w + w = 3w
4 + 3w = 3(w + -1) + 6

Reorder the terms:
4 + 3w = 3(-1 + w) + 6
4 + 3w = (-1 * 3 + w * 3) + 6
4 + 3w = (-3 + 3w) + 6

Reorder the terms:
4 + 3w = -3 + 6 + 3w

Combine like terms: -3 + 6 = 3
4 + 3w = 3 + 3w

Add '-3w' to each side of the equation.
4 + 3w + -3w = 3 + 3w + -3w

Combine like terms: 3w + -3w = 0
4 + 0 = 3 + 3w + -3w
4 = 3 + 3w + -3w

Combine like terms: 3w + -3w = 0
4 = 3 + 0
4 = 3

Solving
4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.