2(w+2)-w=3(w-1)=9

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Solution for 2(w+2)-w=3(w-1)=9 equation:



2(w+2)-w=3(w-1)=9
We move all terms to the left:
2(w+2)-w-(3(w-1))=0
We add all the numbers together, and all the variables
-1w+2(w+2)-(3(w-1))=0
We multiply parentheses
-1w+2w-(3(w-1))+4=0
We calculate terms in parentheses: -(3(w-1)), so:
3(w-1)
We multiply parentheses
3w-3
Back to the equation:
-(3w-3)
We add all the numbers together, and all the variables
w-(3w-3)+4=0
We get rid of parentheses
w-3w+3+4=0
We add all the numbers together, and all the variables
-2w+7=0
We move all terms containing w to the left, all other terms to the right
-2w=-7
w=-7/-2
w=3+1/2

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