2(w+3)+w+3=41

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Solution for 2(w+3)+w+3=41 equation: 



2(w+3)+w+3=41

We move all terms to the left:

2(w+3)+w+3-(41)=0

We add all the numbers together, and all the variables

w+2(w+3)-38=0

We multiply parentheses

w+2w+6-38=0

We add all the numbers together, and all the variables

3w-32=0

We move all terms containing w to the left, all other terms to the right

3w=32

w=32/3

w=10+2/3

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