2(w+3)-10=6(32-w)

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Solution for 2(w+3)-10=6(32-w) equation: 



2(w+3)-10=6(32-w)

We move all terms to the left:

2(w+3)-10-(6(32-w))=0

We add all the numbers together, and all the variables

2(w+3)-(6(-1w+32))-10=0

We multiply parentheses

2w-(6(-1w+32))+6-10=0



We calculate terms in parentheses: -(6(-1w+32)), so:

6(-1w+32)

We multiply parentheses

-6w+192

Back to the equation:

-(-6w+192)



We add all the numbers together, and all the variables

2w-(-6w+192)-4=0

We get rid of parentheses

2w+6w-192-4=0

We add all the numbers together, and all the variables

8w-196=0

We move all terms containing w to the left, all other terms to the right

8w=196

w=196/8

w=24+1/2

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