2(w+3)=-2(3w-2)+2w

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Solution for 2(w+3)=-2(3w-2)+2w equation: 



2(w+3)=-2(3w-2)+2w

We move all terms to the left:

2(w+3)-(-2(3w-2)+2w)=0

We multiply parentheses

2w-(-2(3w-2)+2w)+6=0



We calculate terms in parentheses: -(-2(3w-2)+2w), so:

-2(3w-2)+2w

We add all the numbers together, and all the variables

2w-2(3w-2)

We multiply parentheses

2w-6w+4

We add all the numbers together, and all the variables

-4w+4

Back to the equation:

-(-4w+4)



We get rid of parentheses

2w+4w-4+6=0

We add all the numbers together, and all the variables

6w+2=0

We move all terms containing w to the left, all other terms to the right

6w=-2

w=-2/6

w=-1/3

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