2(w+4)=-2(5w-3)+8w

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Solution for 2(w+4)=-2(5w-3)+8w equation: 



2(w+4)=-2(5w-3)+8w

We move all terms to the left:

2(w+4)-(-2(5w-3)+8w)=0

We multiply parentheses

2w-(-2(5w-3)+8w)+8=0



We calculate terms in parentheses: -(-2(5w-3)+8w), so:

-2(5w-3)+8w

We add all the numbers together, and all the variables

8w-2(5w-3)

We multiply parentheses

8w-10w+6

We add all the numbers together, and all the variables

-2w+6

Back to the equation:

-(-2w+6)



We get rid of parentheses

2w+2w-6+8=0

We add all the numbers together, and all the variables

4w+2=0

We move all terms containing w to the left, all other terms to the right

4w=-2

w=-2/4

w=-1/2

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