2(w-3)=2w+8-2(-7w-2)

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Solution for 2(w-3)=2w+8-2(-7w-2) equation: 



2(w-3)=2w+8-2(-7w-2)

We move all terms to the left:

2(w-3)-(2w+8-2(-7w-2))=0

We multiply parentheses

2w-(2w+8-2(-7w-2))-6=0



We calculate terms in parentheses: -(2w+8-2(-7w-2)), so:

2w+8-2(-7w-2)

determiningTheFunctionDomain
2w-2(-7w-2)+8

We multiply parentheses

2w+14w+4+8

We add all the numbers together, and all the variables

16w+12

Back to the equation:

-(16w+12)



We get rid of parentheses

2w-16w-12-6=0

We add all the numbers together, and all the variables

-14w-18=0

We move all terms containing w to the left, all other terms to the right

-14w=18

w=18/-14

w=-1+2/7

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