2(w-4)(w+6)=832

Solution for 2(w-4)(w+6)=832 equation:

2(w-4)(w+6)=832

We move all terms to the left:

2(w-4)(w+6)-(832)=0

We multiply parentheses ..

2(+w^2+6w-4w-24)-832=0

We multiply parentheses

2w^2+12w-8w-48-832=0

We add all the numbers together, and all the variables

2w^2+4w-880=0

a = 2; b = 4; c = -880;
Δ = b2-4ac
Δ = 42-4·2·(-880)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-84}{2*2}=\frac{-88}{4}
=-22
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+84}{2*2}=\frac{80}{4}
=20
$