2(w-4)+5=3(w-1)

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Solution for 2(w-4)+5=3(w-1) equation: 



2(w-4)+5=3(w-1)

We move all terms to the left:

2(w-4)+5-(3(w-1))=0

We multiply parentheses

2w-(3(w-1))-8+5=0



We calculate terms in parentheses: -(3(w-1)), so:

3(w-1)

We multiply parentheses

3w-3

Back to the equation:

-(3w-3)



We add all the numbers together, and all the variables

2w-(3w-3)-3=0

We get rid of parentheses

2w-3w+3-3=0

We add all the numbers together, and all the variables

-w=0

w=0/-1

w=0

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