2(x)+2(3x-4)=64

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Solution for 2(x)+2(3x-4)=64 equation: 



2(x)+2(3x-4)=64

We move all terms to the left:

2(x)+2(3x-4)-(64)=0

We multiply parentheses

2x+6x-8-64=0

We add all the numbers together, and all the variables

8x-72=0

We move all terms containing x to the left, all other terms to the right

8x=72

x=72/8

x=9

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