2(x*2-19)=(2x+7)(x-4)

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Solution for 2(x*2-19)=(2x+7)(x-4) equation: 



2(x*2-19)=(2x+7)(x-4)

We move all terms to the left:

2(x*2-19)-((2x+7)(x-4))=0

We multiply parentheses

4x-((2x+7)(x-4))-38=0

We multiply parentheses ..

-((+2x^2-8x+7x-28))+4x-38=0



We calculate terms in parentheses: -((+2x^2-8x+7x-28)), so:

(+2x^2-8x+7x-28)

We get rid of parentheses

2x^2-8x+7x-28

We add all the numbers together, and all the variables

2x^2-1x-28

Back to the equation:

-(2x^2-1x-28)



We add all the numbers together, and all the variables

4x-(2x^2-1x-28)-38=0

We get rid of parentheses

-2x^2+4x+1x+28-38=0

We add all the numbers together, and all the variables

-2x^2+5x-10=0

a = -2; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·(-2)·(-10)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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