2(x*x)+6=(x*x)+70

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Solution for 2(x*x)+6=(x*x)+70 equation:



2(x*x)+6=(x*x)+70
We move all terms to the left:
2(x*x)+6-((x*x)+70)=0
We add all the numbers together, and all the variables
2(+x*x)-((+x*x)+70)+6=0
We multiply parentheses
2x^2-((+x*x)+70)+6=0
We calculate terms in parentheses: -((+x*x)+70), so:
(+x*x)+70
We get rid of parentheses
x*x+70
Wy multiply elements
x^2+70
Back to the equation:
-(x^2+70)
We get rid of parentheses
2x^2-x^2-70+6=0
We add all the numbers together, and all the variables
x^2-64=0
a = 1; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·1·(-64)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*1}=\frac{-16}{2} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*1}=\frac{16}{2} =8 $

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