2(x*x)-35x=48

Solution for 2(x*x)-35x=48 equation:

2(x*x)-35x=48

We move all terms to the left:

2(x*x)-35x-(48)=0

We add all the numbers together, and all the variables

2(+x*x)-35x-48=0

We add all the numbers together, and all the variables

-35x+2(+x*x)-48=0

We multiply parentheses

2x^2-35x-48=0

a = 2; b = -35; c = -48;
Δ = b2-4ac
Δ = -352-4·2·(-48)
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1609}}{2*2}=\frac{35-\sqrt{1609}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1609}}{2*2}=\frac{35+\sqrt{1609}}{4}
$