2(x+(x+1)+(x+2))=168

Solution for 2(x+(x+1)+(x+2))=168 equation:

Simplifying
2(x + (x + 1) + (x + 2)) = 168

Reorder the terms:
2(x + (1 + x) + (x + 2)) = 168

Remove parenthesis around (1 + x)
2(x + 1 + x + (x + 2)) = 168

Reorder the terms:
2(x + 1 + x + (2 + x)) = 168

Remove parenthesis around (2 + x)
2(x + 1 + x + 2 + x) = 168

Reorder the terms:
2(1 + 2 + x + x + x) = 168

Combine like terms: 1 + 2 = 3
2(3 + x + x + x) = 168

Combine like terms: x + x = 2x
2(3 + 2x + x) = 168

Combine like terms: 2x + x = 3x
2(3 + 3x) = 168
(3 * 2 + 3x * 2) = 168
(6 + 6x) = 168

Solving
6 + 6x = 168

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 6x = 168 + -6

Combine like terms: 6 + -6 = 0
0 + 6x = 168 + -6
6x = 168 + -6

Combine like terms: 168 + -6 = 162
6x = 162

Divide each side by '6'.
x = 27

Simplifying
x = 27