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2(x+)=4(x-5)
We move all terms to the left:
2(x+)-(4(x-5))=0
We add all the numbers together, and all the variables
2(+x)-(4(x-5))=0
We multiply parentheses
2x-(4(x-5))=0
We calculate terms in parentheses: -(4(x-5)), so:We get rid of parentheses
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
2x-4x+20=0
We add all the numbers together, and all the variables
-2x+20=0
We move all terms containing x to the left, all other terms to the right
-2x=-20
x=-20/-2
x=+10
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