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2(x+-3)=(x-1)+7
We move all terms to the left:
2(x+-3)-((x-1)+7)=0
We add all the numbers together, and all the variables
2(x-3)-((x-1)+7)=0
We multiply parentheses
2x-((x-1)+7)-6=0
We calculate terms in parentheses: -((x-1)+7), so:We get rid of parentheses
(x-1)+7
We get rid of parentheses
x-1+7
We add all the numbers together, and all the variables
x+6
Back to the equation:
-(x+6)
2x-x-6-6=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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