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2(x+-3)=10x+-6-8x
We move all terms to the left:
2(x+-3)-(10x+-6-8x)=0
We add all the numbers together, and all the variables
2(x-3)-(2x-6)=0
We multiply parentheses
2x-(2x-6)-6=0
We get rid of parentheses
2x-2x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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