2(x+0.6)+5(1,02-x)=0

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Solution for 2(x+0.6)+5(1,02-x)=0 equation: 



2(x+0.6)+5(1.02-x)=0

We add all the numbers together, and all the variables

2(x+0.6)+5(-1x+1.02)=0

We multiply parentheses

2x-5x+1.2+5.1=0

We add all the numbers together, and all the variables

-3x+6.3=0

We move all terms containing x to the left, all other terms to the right

-3x=-6.3

x=-6.3/-3

x=2+0.3/3

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