2(x+1)(x+3)+11=(2x+1)(x+5)

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Solution for 2(x+1)(x+3)+11=(2x+1)(x+5) equation: 



2(x+1)(x+3)+11=(2x+1)(x+5)

We move all terms to the left:

2(x+1)(x+3)+11-((2x+1)(x+5))=0

We multiply parentheses ..

2(+x^2+3x+x+3)-((2x+1)(x+5))+11=0



We calculate terms in parentheses: -((2x+1)(x+5)), so:

(2x+1)(x+5)

We multiply parentheses ..

(+2x^2+10x+x+5)

We get rid of parentheses

2x^2+10x+x+5

We add all the numbers together, and all the variables

2x^2+11x+5

Back to the equation:

-(2x^2+11x+5)



We multiply parentheses

2x^2+6x+2x-(2x^2+11x+5)+6+11=0

We get rid of parentheses

2x^2-2x^2+6x+2x-11x-5+6+11=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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