2(x+1)(x+3)+8=(2x+1)(x+5)

Solution for 2(x+1)(x+3)+8=(2x+1)(x+5) equation:

2(x+1)(x+3)+8=(2x+1)(x+5)

We move all terms to the left:

2(x+1)(x+3)+8-((2x+1)(x+5))=0

We multiply parentheses ..

2(+x^2+3x+x+3)-((2x+1)(x+5))+8=0


We calculate terms in parentheses: -((2x+1)(x+5)), so:

(2x+1)(x+5)

We multiply parentheses ..

(+2x^2+10x+x+5)

We get rid of parentheses

2x^2+10x+x+5

We add all the numbers together, and all the variables

2x^2+11x+5

Back to the equation:

-(2x^2+11x+5)


We multiply parentheses

2x^2+6x+2x-(2x^2+11x+5)+6+8=0

We get rid of parentheses

2x^2-2x^2+6x+2x-11x-5+6+8=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3