2(x+1)+(2x-2)+x=x+(2x-9)+(x+1)+(x+8)

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Solution for 2(x+1)+(2x-2)+x=x+(2x-9)+(x+1)+(x+8) equation: 



2(x+1)+(2x-2)+x=x+(2x-9)+(x+1)+(x+8)

We move all terms to the left:

2(x+1)+(2x-2)+x-(x+(2x-9)+(x+1)+(x+8))=0

We add all the numbers together, and all the variables

x+2(x+1)+(2x-2)-(x+(2x-9)+(x+1)+(x+8))=0

We multiply parentheses

x+2x+(2x-2)-(x+(2x-9)+(x+1)+(x+8))+2=0

We get rid of parentheses

x+2x+2x-(x+(2x-9)+(x+1)+(x+8))-2+2=0



We calculate terms in parentheses: -(x+(2x-9)+(x+1)+(x+8)), so:

x+(2x-9)+(x+1)+(x+8)

We get rid of parentheses

x+2x+x+x-9+1+8

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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