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2(x+1)+(4x+2)=5(x+3)
We move all terms to the left:
2(x+1)+(4x+2)-(5(x+3))=0
We multiply parentheses
2x+(4x+2)-(5(x+3))+2=0
We get rid of parentheses
2x+4x-(5(x+3))+2+2=0
We calculate terms in parentheses: -(5(x+3)), so:We add all the numbers together, and all the variables
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
6x-(5x+15)+4=0
We get rid of parentheses
6x-5x-15+4=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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