2(x+1)+1=(x-5)+(x-2)

Solution for 2(x+1)+1=(x-5)+(x-2) equation:

2(x+1)+1=(x-5)+(x-2)

We move all terms to the left:

2(x+1)+1-((x-5)+(x-2))=0

We multiply parentheses

2x-((x-5)+(x-2))+2+1=0


We calculate terms in parentheses: -((x-5)+(x-2)), so:

(x-5)+(x-2)

We get rid of parentheses

x+x-5-2

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)


We add all the numbers together, and all the variables

2x-(2x-7)+3=0

We get rid of parentheses

2x-2x+7+3=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation