2(x+1)+3(x+2)+4(x+3)=5(x+4)

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Solution for 2(x+1)+3(x+2)+4(x+3)=5(x+4) equation: 



2(x+1)+3(x+2)+4(x+3)=5(x+4)

We move all terms to the left:

2(x+1)+3(x+2)+4(x+3)-(5(x+4))=0

We multiply parentheses

2x+3x+4x-(5(x+4))+2+6+12=0



We calculate terms in parentheses: -(5(x+4)), so:

5(x+4)

We multiply parentheses

5x+20

Back to the equation:

-(5x+20)



We add all the numbers together, and all the variables

9x-(5x+20)+20=0

We get rid of parentheses

9x-5x-20+20=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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