2(x+1)+3(x+2)=28

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Solution for 2(x+1)+3(x+2)=28 equation: 


Simplifying
2(x + 1) + 3(x + 2) = 28

Reorder the terms:
2(1 + x) + 3(x + 2) = 28
(1 * 2 + x * 2) + 3(x + 2) = 28
(2 + 2x) + 3(x + 2) = 28

Reorder the terms:
2 + 2x + 3(2 + x) = 28
2 + 2x + (2 * 3 + x * 3) = 28
2 + 2x + (6 + 3x) = 28

Reorder the terms:
2 + 6 + 2x + 3x = 28

Combine like terms: 2 + 6 = 8
8 + 2x + 3x = 28

Combine like terms: 2x + 3x = 5x
8 + 5x = 28

Solving
8 + 5x = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 5x = 28 + -8

Combine like terms: 8 + -8 = 0
0 + 5x = 28 + -8
5x = 28 + -8

Combine like terms: 28 + -8 = 20
5x = 20

Divide each side by '5'.
x = 4

Simplifying
x = 4

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