2(x+1)+3(y-3)=1

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Solution for 2(x+1)+3(y-3)=1 equation: 


Simplifying
2(x + 1) + 3(y + -3) = 1

Reorder the terms:
2(1 + x) + 3(y + -3) = 1
(1 * 2 + x * 2) + 3(y + -3) = 1
(2 + 2x) + 3(y + -3) = 1

Reorder the terms:
2 + 2x + 3(-3 + y) = 1
2 + 2x + (-3 * 3 + y * 3) = 1
2 + 2x + (-9 + 3y) = 1

Reorder the terms:
2 + -9 + 2x + 3y = 1

Combine like terms: 2 + -9 = -7
-7 + 2x + 3y = 1

Solving
-7 + 2x + 3y = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 2x + 7 + 3y = 1 + 7

Reorder the terms:
-7 + 7 + 2x + 3y = 1 + 7

Combine like terms: -7 + 7 = 0
0 + 2x + 3y = 1 + 7
2x + 3y = 1 + 7

Combine like terms: 1 + 7 = 8
2x + 3y = 8

Add '-3y' to each side of the equation.
2x + 3y + -3y = 8 + -3y

Combine like terms: 3y + -3y = 0
2x + 0 = 8 + -3y
2x = 8 + -3y

Divide each side by '2'.
x = 4 + -1.5y

Simplifying
x = 4 + -1.5y

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