2(x+1)+3=8(2x-2)-7

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Solution for 2(x+1)+3=8(2x-2)-7 equation: 



2(x+1)+3=8(2x-2)-7

We move all terms to the left:

2(x+1)+3-(8(2x-2)-7)=0

We multiply parentheses

2x-(8(2x-2)-7)+2+3=0



We calculate terms in parentheses: -(8(2x-2)-7), so:

8(2x-2)-7

We multiply parentheses

16x-16-7

We add all the numbers together, and all the variables

16x-23

Back to the equation:

-(16x-23)



We add all the numbers together, and all the variables

2x-(16x-23)+5=0

We get rid of parentheses

2x-16x+23+5=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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