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2(x+1)+4=3(x+2)
We move all terms to the left:
2(x+1)+4-(3(x+2))=0
We multiply parentheses
2x-(3(x+2))+2+4=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
2x-(3x+6)+6=0
We get rid of parentheses
2x-3x-6+6=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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